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Player Profile

Player:

(Eg: Carlsen,Magnus)

Hangweyrer, M



Years:	2022-2023
Number of games:	14
Number of wins:	3
Number of draws:	9
Number of losses:	2
White score:	2½/5 (50% - Average Elo: 2278.2)
Black score:	5/9 (55.56% - Average Elo: 2283.33)

Games
White wins
White draws
White losses
Black wins
Black draws
Black losses

Top wins

Hangweyrer, M (2310) - Bauer, Thomas (2201), TCh-AUT 2nd Ost 2021-22, Austria AUT (A04) - 2022

Konaplev, Anton (2290) - Hangweyrer, M (2296), TCh-AUT 2nd Ost 2022-23, Austria AUT (C41) - 2023

Rainprecht, B (2067) - Hangweyrer, M (2296), TCh-AUT 2nd Ost 2022-23, Austria AUT (A36) - 2022

Hangweyrer, M - ? (5)

Bauer, Thomas (1/1)

Belke, F (½/1)

Jablonicky, Martin (0/1)

Videki, S (½/1)

Wagner, Leopold Franziskus (½/1)

? - Hangweyrer, M (8)

Ganaus, H (1/2)

Alvir, A (½/1)

Dotzer, Lukas (½/1)

Juhasz, Kr (½/1)

Konaplev, Anton (1/1)

Morgunov, Marc (0/1)

Rainprecht, B (1/1)

Schulz, Jo (½/1)

Openings played as White (5)

A04 Reti Opening (1.Nf3)
Average Elo: 2201
Result: 1/1 = 100%

D79 Neo-Grunfeld, 6.O-O, Main line (1.d4 Nf6 2.c4 g6 3.g3 d5 4.Bg2 Bg7 5.Nf3 O-O 6.O-O c6 7.cxd5 cxd5)
Average Elo: 2258
Result: ½/1 = 50%

B20 Sicilian (1.e4 c5)
Average Elo: 2356
Result: 0/1 = 0%

B30 Sicilian (1.e4 c5 2.Nf3 Nc6)
Average Elo: 2394
Result: ½/1 = 50%

A07 King's Indian Attack (1.Nf3 d5 2.g3)
Average Elo: 2182
Result: ½/1 = 50%

Openings played as Black (7)

B32 Sicilian (1.e4 c5 2.Nf3 Nc6 3.d4 cxd4 4.Nxd4 e5)
Average Elo: 2278
Result: ½/2 = 25%

A11 English, Caro-Kann Defensive System (1.c4 c6)
Average Elo: 2360
Result: 1/2 = 50%

B06 Robatsch (1.e4 g6)
Average Elo: 2298
Result: ½/1 = 50%

D14 Queen's Gambit Declined Slav, Exchange Variation (1.d4 d5 2.c4 c6 3.Nf3 Nf6 4.cxd5 cxd5 5.Nc3 Nc6 6.Bf4 Bf5)
Average Elo: 2280
Result: ½/1 = 50%

A36 English (1.c4 c5 2.Nc3 Nc6 3.g3)
Average Elo: 2067
Result: 1/1 = 100%

C41 Philidor Defense (1.e4 e5 2.Nf3 d6)
Average Elo: 2290
Result: 1/1 = 100%

B25 Sicilian, Closed (1.e4 c5 2.Nc3 Nc6 3.g3 g6 4.Bg2 Bg7 5.d3 d6)
Average Elo: 2339
Result: ½/1 = 50%